How to order and partition by various columns?

199    Asked by ChristianParsons in SQL Server , Asked on Aug 3, 2023

I am deploying PostgreSQL. There is a table having 2 columns int he figure below:

I need to include a new column having a distinct id respective to partitions by name and category. Then, I need a random sample selecting 2 distinct ids since under every id, there will be a huge amount of historical data.  I want to know how to correct my mistakes.

SELECT
  dense_rank() over (partition by name, category order by category) as unique_id,
  *
FROM
 example_table
After this, presumably I'll have to use RAND() somewhere but how do I do this?


Answered by Danna sahi

 You can utilize roe number () function to arrange and par the columns.

SELECT
    name,
    category,
          ROW_NUMBER() OVER (PARTITION BY name, category ORDER BY name, category) unique_id

FROM

    test;
name | category | unique_id
:--- | :------- | --------:
A | Alpha | 1
A | Alpha | 2
A | Alpha | 3
A | Beta | 1
A | Beta | 2
B | Alpha | 1
B | Alpha | 2
B | Theta | 1
db<>fiddle here
To get a unique_id for each pair of name-category, remove the PARTITION part and use only ORDER BY:
SELECT
    name,
    category,
    DENSE_RANK() OVER (ORDER BY name, category) unique_id
FROM
    test;
name | category | unique_id
:--- | :------- | --------:
A | Alpha | 1
A | Alpha | 1
A | Alpha | 1
A | Beta | 2
A | Beta | 2
B | Alpha | 3
B | Alpha | 3
B | Theta | 4
db<>fiddle here
To select two rows of each unique_id: (As far as I've not used any order it is supposed to be random)
WITH ct AS
(
  SELECT
      name,
      category,
      DENSE_RANK() OVER (ORDER BY name, category) unique_id
  FROM
      test
)
SELECT
    a.unique_id, c.name, c.category
FROM
    (SELECT DISTINCT unique_id
     FROM ct) a
JOIN LATERAL (SELECT b.name, b.category
              FROM ct b
              WHERE b.unique_id = a.unique_id
              LIMIT 2) c ON TRUE
ORDER BY
    a.unique_id;
unique_id | name | category
--------: | :--- | :-------
        1 | A | Alpha
        1 | A | Alpha
        2 | A | Beta
        2 | A | Beta
        3 | B | Alpha
        3 | B | Alpha
        4 | B | Theta
You can also try the below-mentioned code:
SELECT * FROM (
            SELECT
                [Code],
                [Name],
                [CategoryCode],
                [CreatedDate],
                [ModifiedDate],
                [CreatedBy],
                [ModifiedBy],
                [IsActive],
                ROW_NUMBER() OVER(PARTITION BY [Code],[Name],[CategoryCode] ORDER BY ID DESC) rownumber
            FROM MasterTable
          ) a
        WHERE rownumber = 1

When the table columns have similar data and when you directly apply row_number() and make PARTITION on column, the result in a duplicate row with row number value appears. To erase duplicate row, one more INNER query is needed from clause that removes replicate rows and gives result to the outer FROM clause where you can sue PARTITION and ROW_NUMBER ()>

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