How to parse JSON in Java

54    Asked by neeraj_7175 in Java , Asked on Apr 18, 2025

Parsing JSON in Java can seem tricky at first, but with the right tools like Jackson or Gson, it becomes simple and efficient. This guide explains how to read, convert, and use JSON data easily within your Java applications.

Answered by Ono Imai

Parsing JSON in Java is a common task when working with APIs or external data sources. Thankfully, Java has several libraries that simplify this process—two of the most popular are Jackson and Gson. Both libraries help convert JSON strings into Java objects and vice versa.

Here’s how you can approach JSON parsing in Java:

Using Jackson:

Add dependency: If you're using Maven, add the Jackson library:


  com.fasterxml.jackson.core
  jackson-databind
  2.x.x

Parse JSON:

ObjectMapper mapper = new ObjectMapper();
MyClass obj = mapper.readValue(jsonString, MyClass.class);

 Using Gson:

Add dependency:


  com.google.code.gson
  gson
  2.x

Parse JSON:

Gson gson = new Gson();
MyClass obj = gson.fromJson(jsonString, MyClass.class);

 Things to Keep in Mind:

  • Your Java class (MyClass) should match the structure of the JSON data.
  • Both libraries can handle nested JSON, lists, and complex objects.
  • If you need pretty printing or custom serialization, both libraries support that as well.

So, while Java doesn’t have built-in JSON parsing like some languages, libraries like Jackson and Gson make it smooth and reliable.



Your Answer

Answer (1)

While I appreciate the explanation of Jackson and Gson, and agree they simplify JSON parsing, I wonder if focusing solely on library usage overlooks the importance of understanding the underlying JSON structure and potential validation issues. Over-reliance on libraries can sometimes mask fundamental data handling principles, leading to problems down the line. Perhaps exploring those foundational elements alongside library implementation would offer a more comprehensive approach. Neglecting that basis can feel like bad parenting



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